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5x-10=x^2+40
We move all terms to the left:
5x-10-(x^2+40)=0
We get rid of parentheses
-x^2+5x-40-10=0
We add all the numbers together, and all the variables
-1x^2+5x-50=0
a = -1; b = 5; c = -50;
Δ = b2-4ac
Δ = 52-4·(-1)·(-50)
Δ = -175
Delta is less than zero, so there is no solution for the equation
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